If a = 5 & c = 6, then?

Answer 1

#/_A=56.4^circ#

#/_B=33.6^circ#

Since we have a right angled triangle, we can use #sin# and #cos.
#sintheta=O /H# #/_A=theta=sin^-1(O /H)=sin^-1(5/6)~~56.4^circ#
#costheta=A/H# #/_B=theta=cos^-1(A/H)=cos^-1(5/6)~~33.6^circ#
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Answer 2

#angle A =approx 56.44^o#, #angle B approx 33.56^o#

Here we have a right #triangle ABC#
Side #a=5# and side #c=6#
#:. sin A = a/c = 5/6#
#angle A = arcsin (5/6)#
#approx 56.44^o#
Since the sum of the angles of any triangle is #180^o#
#angle B approx 180 - 90 - 56.44#
#approx 33.56^o#
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Answer 3

Without further context or additional information, it's not clear what you're asking for when given the values of (a) and (c). Please provide more details or clarify your question so that I can offer an accurate response.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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