If a #3 kg# object moving at #9 m/s# slows down to a halt after moving #27 m#, what is the coefficient of kinetic friction of the surface that the object was moving over?
The work being done on the object is Work due to friction so the following equation is going to be used:
We can rewrite Equation (a) if we break down both sides step-by-step to become:
Answer: 0.15
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The coefficient of kinetic friction can be calculated using the formula:
[ f_k = \frac{m \cdot g \cdot d}{m \cdot v^2} ]
Where:
- ( m ) is the mass of the object (3 kg),
- ( g ) is the acceleration due to gravity (9.8 m/s²),
- ( d ) is the distance traveled (27 m),
- ( v ) is the initial velocity of the object (9 m/s).
Substituting the values:
[ f_k = \frac{3 \times 9.8 \times 27}{3 \times 9^2} ]
[ f_k = \frac{794.4}{243} ]
[ f_k ≈ 3.27 ]
Therefore, the coefficient of kinetic friction of the surface is approximately 3.27.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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