Home > Physics > Power

If a #2 kg# object is constantly accelerated from #0m/s# to #16 m/s# over # 9 s#, how much power musy be applied at #t=7#?

Answer 1

Leo Abeyta

#44.24 W#

acceleration of the object is #16/9 m/s^2# (using #v=u-at#)

hence force acting on it is,#F#=# m*a# or #32/9 N#

velocity of the object at #7# sec is# 16/9 * 7# or #112/9# #m/s#

hence,power applied at #7# sec is # F*v# or, #32/9 * 112/9# #W# i.e #44.24 W#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Olivia Askew

To calculate power at t=7s, additional information about the acceleration is needed.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.