# If a #2 kg# object is being constantly accelerated from #0m/s# to #15 m/s# over # 6s#, how much power is being applied at #t= 2 #?

The power is

Apply the equation of motion

To calculate the acceleration

According to Newton's Second Law

The force is

The power is

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To calculate power at ( t = 2 ) seconds, we use the formula ( P = F \cdot v ). First, find acceleration using ( a = \frac{\Delta v}{\Delta t} ). Then, find force using ( F = m \cdot a ). Finally, calculate power using ( P = F \cdot v ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- What are some examples of work?

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