If #9 L# of a gas at room temperature exerts a pressure of #9 kPa# on its container, what pressure will the gas exert if the container's volume changes to #4 L#?
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Using Boyle's Law, we can calculate the new pressure using the formula:
P1V1 = P2V2
Substituting the given values:
(9 kPa)(9 L) = P2(4 L)
Solving for P2:
P2 = (9 kPa * 9 L) / 4 L
P2 = 81 kPa / 4
P2 = 20.25 kPa
Therefore, the gas will exert a pressure of approximately 20.25 kPa when the container's volume changes to 4 L.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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