If #8 L# of a gas at room temperature exerts a pressure of #45 kPa# on its container, what pressure will the gas exert if the container's volume changes to #9 L#?
The gas will exert a pressure of 40 kPa.
We can obtain the final pressure via Boyle's Law:
Let's identify the known and unknown variables:
- Initial Volume
- Final Volume
- Initial Pressure
- Final Pressure
All we have to do is rearrange the equation to solve for the final pressure. We do this by dividing both sides by Now all we do is plug in the values and we're done!
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Using Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature remains constant, we can calculate the new pressure using the formula:
P1 * V1 = P2 * V2
Where: P1 = initial pressure (45 kPa) V1 = initial volume (8 L) P2 = final pressure (unknown) V2 = final volume (9 L)
Rearranging the formula to solve for P2:
P2 = (P1 * V1) / V2
Substituting the given values:
P2 = (45 kPa * 8 L) / 9 L P2 = 40 kPa
Therefore, the gas will exert a pressure of 40 kPa if the container's volume changes to 9 L.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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