If #8 L# of a gas at room temperature exerts a pressure of #2 kPa# on its container, what pressure will the gas exert if it the container's volume changes to #1 L#?

Answer 1

The final pressure is #16 kPa#

Let's identify the known and unknown variables:

#color(yellow)("Knowns:")#
- Initial Volume
- Final Volume
- Initial Pressure

#color(orange)("Unknowns:")#
- Final Pressure

We can obtain the answer using Boyle's Law:

The letters i and f represent the initial and final conditions, respectively.

All we have to do is rearrange the equation to solve for the final pressure.

We do this by dividing both sides by #V_f# in order to get #P_f# by itself like this:
#P_f=(P_ixxV_i)/V_f#

Now all we do is plug in the values and we're done!

#P_f= (2kPa xx 8cancel"L")/(1\cancel"L")# = #16kPa#

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Answer 2

The pressure of the gas will be 16 kPa.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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