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If #7/4 L# of a gas at room temperature exerts a pressure of #15 kPa# on its container, what pressure will the gas exert if the container's volume changes to #5/3 L#?

Answer 1

Olivia Askew

#P_2=15,75 kPa#

#V_1=7/4 L#

#P_1=15kPa#

#V_2=5/3 L#

#P_2=?#

#P_1*V_1=P_2*V_2" Boyle's law"#

#cancel(15)*7/4=P_2*cancel(5)/3#

#21/4=P_2*1/3#

#P_2=(3*21)/4#

#P_2=63/4#

#P_2=15,75 kPa#

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Answer 2

Emily Abbate

The pressure of the gas will be approximately 21.43 kPa.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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