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If 60 liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, what will the new volume of the gas be?

Answer 1

Data:- Initial Volume#=V_1=60 liter# Initial Temperature#=T_1=546K# Final Temperature#=T_2=273K# Final Vloume#=V_2=??# Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e, #V_1/T_1=V_2/T_2#

#implies V_2=(V_1*T_2)/T_1=(60*273)/546=60/2=30liter#

#implies V_2=30 liter#

Hence the new volume of the gas is #30 liter#

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Answer 2

Cooper Anderson

To find the new volume of the gas, you can use the combined gas law:

[ \frac{{V_1}}{{T_1}} = \frac{{V_2}}{{T_2}} ]

Where:

( V_1 = 60 ) liters (initial volume)
( T_1 = 546 ) K (initial temperature)
( T_2 = 273 ) K (final temperature)

[ V_2 = V_1 \times \frac{{T_2}}{{T_1}} ]

Substitute the values into the equation and solve for ( V_2 ):

[ V_2 = 60 \times \frac{{273}}{{546}} ]

[ V_2 = 30 ] liters

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.