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If # 3a + 1= \frac { 13} { 3}#, what is the value of #3a - 3#?

Answer 1

Avery Alexander

The value of #3a-3# is #1/3#.

To get #3a-3#, just subtract #4# from both sides of the equation:

#3a+1=13/3#

#3a+1color(blue)-color(blue)4=13/3color(blue)-color(blue)4#

#3a-3=13/3color(blue)-color(blue)4#

#3a-3=13/3color(blue)-color(blue)(12/3)#

#3a-3=(13color(blue)-color(blue)12)/3#

#3a-3=1/3#

Hope this helped!

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Answer 2

Ethan Adkins

#color(indigo)(=>1/3#

#3a + 1 = 13/3#

#3a = 13/3 - 1#

#3a = (13-3) / 3 = 10/3#

Subtracting 3 on both sides,

#3a - 3 = 10/3 - 3 = (10-9)/3 = 1/3#

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Answer 3

Julia Adams

If 3a + 1 = 13/3, then 3a - 3 can be found by first solving for the value of a in 3a + 1 = 13/3, and then substituting that value into 3a - 3.

Step 1: Solve for a: 3a + 1 = 13/3 3a = 13/3 - 1 3a = 13/3 - 3/3 3a = (13 - 3) / 3 3a = 10/3 a = (10/3) / 3 a = 10/9

Step 2: Substitute the value of a into 3a - 3: 3a - 3 = (3 * 10/9) - 3 3a - 3 = 10/3 - 3 3a - 3 = (10 - 9) / 3 3a - 3 = 1/3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.