If #32 L# of a gas at room temperature exerts a pressure of #6 kPa# on its container, what pressure will the gas exert if the container's volume changes to #2 L#?

Answer 1

96kPa will be the pressure exerted by gas in container, if its volume changes to 2L.

Assume that the two volumes' (32L and 2L) respective temperatures stay the same.

Example 1:

#V_1=32L#
#P_1 =6000 Pa#

instance ii:

#V_2=2L#
#P_2=?#

We are aware of that

#V_1prop1/(P_1)##------(1)#
#V_2 prop 1/(P_2)##------(2)#
doing #(1)//(2)#
#(V_1)/(V_2)=(P_2)/(P_1)#

replace the given information in the equation above.

#32/2=(P_2)/6000#
#P_2=16xx6000#
#P_2=96000 Pa#
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Answer 2

The pressure of the gas will be 96 kPa when the container's volume changes to 2 L.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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