If 3^(x)-3^(x-1)=18 the value of 2^x is?
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To find the value of ( 2^x ), we first solve the equation ( 3^x - 3^{x-1} = 18 ) for ( x ):
[ 3^x - 3^{x-1} = 18 ]
[ 3^x - \frac{3^x}{3} = 18 ]
[ 3^x - \frac{1}{3} \times 3^x = 18 ]
[ \frac{2}{3} \times 3^x = 18 ]
[ 3^x = \frac{18 \times 3}{2} ]
[ 3^x = 27 ]
[ x = \log_3(27) ]
[ x = 3 ]
Now that we have found the value of ( x ), we can find the value of ( 2^x ):
[ 2^x = 2^3 ]
[ 2^x = 8 ]
So, the value of ( 2^x ) is ( 8 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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