If 250g of sugar is completely fermented to ethanol, what is the theoretical yield of ethyl alcohol in: ?
i. grams or milliliters (density of ethanol is 0.79g/mL)
ii. what is the final %v/v of alcohol if that 250 sugar was used to make 1L of wine? (assume no volume changed during fermentation)
please, show me the working out.
Thanks
i. grams or milliliters (density of ethanol is 0.79g/mL)
ii. what is the final %v/v of alcohol if that 250 sugar was used to make 1L of wine? (assume no volume changed during fermentation)
please, show me the working out.
Thanks
i. The theoretical yield of ethanol is 135 g or 170 mL; ii.the final concentration is 17 % v/v.
Let's compile all the data in one location since we know we'll need a balanced equation with masses and moles.
Determine the moles of sugar in step 1.
Step 2: Determine the ethanol moles.
Step 3: Determine the ethanol's mass.
Step 4: Determine the ethanol volume.
Step 5: Determine the ethanol volume percentage.
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Here's what I got.
Start by writing the chemical equation that describes this reaction
If you were supposed to work with sucrose instead of glucose, add this step
This means that the reaction will produce
To convert this to grams, use the molar mass of ethanol
Rounded to two sig figs, the answer will be
To convert this to milliliters, use the density of ethanol
Therefore, the concentration by volume will be
I'll leave the answer rounded to two sig figs, but don't forget that you only have one significant figure for the volume of wine.
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To determine the theoretical yield of ethanol produced from the fermentation of 250g of sugar, we need to use the stoichiometry of the reaction. The balanced chemical equation for the fermentation of sugar (glucose) to ethanol and carbon dioxide is:
C6H12O6 → 2 C2H5OH + 2 CO2
From the balanced equation, we can see that 1 mole of glucose produces 2 moles of ethanol. The molar mass of glucose (C6H12O6) is approximately 180 g/mol.
First, we need to convert the mass of sugar (250g) to moles: 250g / 180 g/mol = 1.39 moles of sugar
Since the molar ratio of sugar to ethanol is 1:2, we multiply the number of moles of sugar by 2 to find the number of moles of ethanol produced: 1.39 moles of sugar × 2 = 2.78 moles of ethanol
Now, we convert the moles of ethanol to grams using the molar mass of ethanol (C2H5OH), which is approximately 46 g/mol: 2.78 moles × 46 g/mol = 127.88g
Therefore, the theoretical yield of ethanol produced from the fermentation of 250g of sugar is approximately 127.88 grams.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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