# If #24 L# of a gas at room temperature exerts a pressure of #8 kPa# on its container, what pressure will the gas exert if the container's volume changes to #15 L#?

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We can use Boyle's Law to solve this problem, which states that the pressure of a gas is inversely proportional to its volume when the temperature remains constant.

Boyle's Law equation: [ P_1 \cdot V_1 = P_2 \cdot V_2 ]

Where:

- ( P_1 ) is the initial pressure (8 kPa)
- ( V_1 ) is the initial volume (24 L)
- ( P_2 ) is the final pressure (unknown)
- ( V_2 ) is the final volume (15 L)

Substitute the given values into the equation: [ 8 \times 24 = P_2 \times 15 ] [ 192 = 15P_2 ] [ P_2 = \frac{192}{15} ] [ P_2 \approx 12.8 \text{ kPa} ]

Therefore, the gas will exert a pressure of approximately 12.8 kPa when the container's volume changes to 15 L.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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