Home > Physics > Gas Laws

If #2 L# of a gas at room temperature exerts a pressure of #35 kPa# on its container, what pressure will the gas exert if the container's volume changes to #12 L#?

Answer 1

Isabella Alvarez

#5.83 kPa#

Let's identify the known and unknown variables:

#color(violet)("Knowns:")#
- Initial Volume
- Final Volume
- Initial Pressure

#color(orange)("Unknowns:")#
- Final Pressure

We can obtain the answer using Boyle's Law

The numbers 1 and 2 represent the initial and final conditions, respectively.

All we have to do is rearrange the equation to solve for the final pressure.

We do this by dividing both sides by #V_2# in order to get #P_2# by itself like this:
#P_2=(P_1xxV_1)/V_2#

Now all we do is plug in the values and we're done!

#P_2= (35kPa xx 2cancel"L")/(12\cancel"L")# = #5.83kPa#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Nicholas Agrusa

Using Boyle's Law, P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

P2 = (P1 * V1) / V2

P2 = (35 kPa * 2 L) / 12 L

P2 ≈ 5.83 kPa

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.