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If #19 L# of a gas at room temperature exerts a pressure of #2 kPa# on its container, what pressure will the gas exert if the container's volume changes to #7 L#?

Answer 1

Charles Aeschliman

#P_2=5,43" " kPa#

#"We can use the Boyle's law"# #P_1*V_1=P_2*V_2# #2*19=P_2*7# #P_2=(2*19)/7#

#P_2=38/7# #P_2=5,43" " kPa#

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Answer 2

Leo Abeyta

( P_1 \cdot V_1 = P_2 \cdot V_2 )

( (2 , \text{kPa}) \cdot (19 , \text{L}) = P_2 \cdot (7 , \text{L}) )

( P_2 = \frac{(2 , \text{kPa}) \cdot (19 , \text{L})}{7 , \text{L}} )

( P_2 \approx 5.43 , \text{kPa} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.