If #18 L# of a gas at room temperature exerts a pressure of #15 kPa# on its container, what pressure will the gas exert if the container's volume changes to #5 L#?

Answer 1

Olivia Askew

#54kPa#

Let's identify the known and unknown variables:

#color(orange)("Knowns:")#
- Initial Volume
- Final Volume
- Initial Pressure

#color(gray)("Unknowns:")#
- Final Pressure

We can obtain the answer using Boyle's Law

The numbers 1 and 2 represent the initial and final conditions, respectively.

All we have to do is rearrange the equation to solve for the final pressure.

We do this by dividing both sides by #V_2# in order to get #P_2# by itself like this:
#P_2=(P_1xxV_1)/V_2#

Now all we do is plug in the values and we're done!

#P_2= (15kPa xx 18cancel"L")/(5\cancel"L")# = #54kPa#

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Answer 2

Axel Acevedo

The pressure the gas will exert if the container's volume changes to 5 L is approximately 54 kPa.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.