If 15 moles of water was made in this reaction, how many grams of carbon dioxide were made? #H_2CO_3rarrH_2O+CO_2#

Answer 1

#660.15"g"# of carbon dioxide was produced.

We have the equation #H_2CO_3rarrH_2O+CO_2#.
The moles of water and carbon dioxide are in the ratio #1:1#.
So #15# moles of water and #15# moles of carbon dioxide are produced.
The formula for moles is #n=m/M#, where #m# is the mass of the substance and #M# its molar mass.
Rearranging the equation we get #m=nM#.
We have #15"mol"# of carbon dioxide and the molar mass of the gas is #44.01"g"/"mol"#.

Entering:

#m=15*44.01#
#m=660.15"g"# of carbon dioxide was produced.
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Answer 2

The molar ratio of H₂O to CO₂ in the reaction is 1:1. Therefore, 15 moles of water would result in 15 moles of carbon dioxide. Given the molar mass of carbon dioxide (CO₂) is approximately 44 grams/mol, 15 moles would correspond to 660 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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