If 10 mol of #CaC_2# reacts with #H_2O#, how many moles of #C_2H_2# will be produced?

#CaC_2 + 2H_2O -> Ca(OH)_2 + C_2H_2#

Answer 1

This is an acid base reaction.............

With water......

#Ca^(2+){C-=C}^(2-)+2H_2Orarr Ca(OH)_2+HC-=CH(g)uarr#
And the stoichiometry clearly indicates that ONE mole of calcium carbide, a mass of #64.1*g# reacts with TWO moles of water, #36*g# to give #74.1*g# calcium hydroxide, and #26*g# acetylene.

Is mass conserved in this reaction? Should it be?

And if you decompose #10* mol# calcium carbide you clearly gets #10* mol# acetylene. Agreed?
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Answer 2
#"10 mols"# of #"C"_2"H"_2#.

I believe you've already overcome the difficult part because you have the chemical reaction balanced. Now that we have the chemical reaction, we can use it. By reading the coefficients, we can obtain the stoichiometric ratios.

As an illustration...

For every one mol of #"CaC"_2#, one mol of #"Ca"("OH")_2# is produced.
For every one mol of #"CaC"_2#, one mol of #"C"_2"H"_2# is produced.
For every one mol of #"CaC"_2#, two mols of water react.

You did not specify how much water reacts, so we assume that there is excess water.... and so on.

From the second bullet point, we know that #"CaC"_2# and #"C"_2"H"_2# have a #1:1# mol ratio. For emphasis, this is saying:
#color(red)(1)CaC_2 + 2H_2O -> Ca(OH)_2 + color(red)(1)C_2H_2#
So, you apparently already have the number written down. It is #color(blue)("10 mols")# of #"C"_2"H"_2# that is produced (assuming the water is in excess).
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Answer 3

2 moles of C2H2 will be produced.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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