If 1 mole of H2 gas was collected under 294.2K and 746.7 mmHg, what volume will it occupy?

Answer 1

Well, #V=(nRT)/P#, and of course, we must choose the appropriate gas constant; #R=0.0821*L*atm*K^-1*mol^-1# is used here.

The key to solving these problems is to recall that #1*atm# of pressure will support a column of mercury that is #760*mm# high. A column of mercury may thus be used to measure pressures up to #1*atm#.
And so #V=(1*molxx0.0821*(L*atm)/(K*mol)xx294.2*K)/((746.7*mm*Hg)/(760*mm*Hg*atm^-1)#
#=??L#. It should be about #25*L#.
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Answer 2

Using the ideal gas law equation (PV = nRT), where:

  • (P) is the pressure (in atmospheres)
  • (V) is the volume (in liters)
  • (n) is the number of moles
  • (R) is the ideal gas constant (0.0821 L·atm/mol·K)
  • (T) is the temperature (in Kelvin)

Given:

  • (n = 1 \text{ mole})
  • (T = 294.2 \text{ K})
  • (P = 746.7 \text{ mmHg})

First, we need to convert pressure from mmHg to atm: [ P = 746.7 \text{ mmHg} \times \frac{1 \text{ atm}}{760 \text{ mmHg}} = 0.981 \text{ atm} ]

Now, rearranging the ideal gas law equation to solve for volume ((V)): [ V = \frac{nRT}{P} ]

Substituting the given values: [ V = \frac{(1 \text{ mol})(0.0821 \text{ L} \cdot \text{atm/mol} \cdot \text{K})(294.2 \text{ K})}{0.981 \text{ atm}} ]

[ V = 24.53 \text{ L} ]

Therefore, 1 mole of H2 gas collected under 294.2 K and 746.7 mmHg will occupy approximately 24.53 liters.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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