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If #1/4x=5-1/2y#, what is the value of x+2y?

Answer 1

Kennedy Adams

#x+2y =20#

First, eliminate the decimals from the given equation to make it simpler.

#1/4x=5-1/2y" "larr xx 4#

#4xx 1/4x= 4xx5 -4xx1/2y#

#x = 20-2y" "larr# the variables are almost what we need.

We get exactly what we want when we rearrange.

#x+2y =20#

Keep in mind that the equation has an infinite number of solutions rather than a single, unique solution because there are two variables.

(This is a straight line's equation.)

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Answer 2

Isaiah Anthony

To find the value of ( x + 2y ), we need to first solve the equation ( \frac{1}{4}x = 5 - \frac{1}{2}y ) for either ( x ) or ( y ), and then substitute the obtained value(s) into the expression for ( x + 2y ). Let's solve for ( x ):

[ \frac{1}{4}x = 5 - \frac{1}{2}y ] [ x = 4(5 - \frac{1}{2}y) ] [ x = 20 - 2y ]

Now, substitute ( x = 20 - 2y ) into ( x + 2y ):

[ (20 - 2y) + 2y = 20 ]

Therefore, the value of ( x + 2y ) is ( 20 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.