If #1/3(x-1)^3+2#, what are the points of inflection, concavity and critical points?

Answer 1

The point of inflection is #=(1,2)#. The interval of concavity is #x in (-oo,1)#. The interval of convexity is #(1,+oo)#

Let #f(x)=1/3(x-1)^3+2#
Let's develop #f(x)#
#f(x)=1/3(x^3-3x^2+3x-1)+2#
#=x^3/3-x^2+x+5/3#

Calculate the first derivative

#f'(x)=x^2-2x+1=(x-1)^2#
The critical points are when #f'(x)=0#

That is,

#(x-1)^2=0#, #=>#, #x=1#

Now, calculate the second derivative

#f''(x)=2x-2#
The points of inflections are when #f''(x)=0#

That is,

#2x-2=0#, #=>#, #x=1#

Make a sign chart

#color(white)(aaaa)##Interval##color(white)(aaaa)##(-oo,1)##color(white)(aaaa)##(1,+oo)#
#color(white)(aaaa)##Sign f''(x)##color(white)(aaaaa)##-##color(white)(aaaaaaaa)##+#
#color(white)(aaaa)## f(x)##color(white)(aaaaaaaaaaa)##nn##color(white)(aaaaaaaa)##uu#

graph{1/3(x-1)^3+2 [-8.335, 9.445, -2.355, 6.534]}

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Answer 2
To find the points of inflection, concavity, and critical points of the function \( f(x) = \frac{1}{3}(x-1)^3 + 2 \), follow these steps: 1. **Find the first derivative of the function:** \[ f'(x) = (x-1)^2 \] 2. **Set the first derivative equal to zero and solve for \( x \) to find critical points:** \[ (x-1)^2 = 0 \] \[ x - 1 = 0 \] \[ x = 1 \] 3. **Find the second derivative of the function:** \[ f''(x) = 2(x-1) \] 4. **Determine the concavity by analyzing the sign of the second derivative:** - When \( f''(x) > 0 \), the function is concave up. - When \( f''(x) < 0 \), the function is concave down. 5. **Set the second derivative equal to zero to find points of inflection:** \[ 2(x-1) = 0 \] \[ x - 1 = 0 \] \[ x = 1 \] 6. **Now, evaluate the concavity at \( x = 1 \) to determine if it's a point of inflection:** \[ f''(1) = 2(1-1) = 0 \] - Since \( f''(1) = 0 \), there is no change in concavity at \( x = 1 \), so it's not a point of inflection. 7. **Critical point:** \( x = 1 \) 8. **Concavity:** The function is concave up for \( x < 1 \) and concave down for \( x > 1 \). 9. **Points of Inflection:** There are no points of inflection for the given function.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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