I am having trouble with these! if 75ml of 0.211M NaOH is diluated in a final volume of 125m, what is the concentrration of the new solution?

Question

I am having trouble with these! if 75ml of 0.211M  NaOH is diluated in a final volume of 125m, what is the concentrration of the new solution?

Avery Adams · Accepted Answer

Volume and molarity are generally proportional, since molarity is a measure of moles per unit volume (e.g. liter). #M_1V_1 = M_2V_2# #0.211M * 0.075L = 0.125L * M_2#
#therefore M_2 approx 0.127M# Qualitatively, you can imagine lemon juice tasting less bitter with the addition of water, so the molarity decreasing makes sense.

Cooper Adams · Answer

undefined To find the concentration of the new solution after dilution, we can use the dilution formula, which states that the initial concentration multiplied by the initial volume equals the final concentration multiplied by the final volume.

Initial concentration of NaOH solution ($C_1$): 0.211 M
Initial volume ($V_1$): 75 mL
Final volume ($V_2$): 125 mL

Using the dilution formula:

$$ C_1 \times V_1 = C_2 \times V_2 $$

Substitute the given values:

$$ 0.211 \, \text{M} \times 75 \, \text{mL} = C_2 \times 125 \, \text{mL} $$

Solve for $ C_2 $:

$$ C_2 = \frac{0.211 \, \text{M} \times 75 \, \text{mL}}{125 \, \text{mL}} $$

$$ C_2 = \frac{15.825}{125} \, \text{M} $$

\[ C_2 = 0.1266 \, \text{M}