Hydrogen was passed over heated 2g copper oxide till only copper was left. The mass of copper obtained was was 1.6 grams. What is the percentage of oxygen in copper oxide?

Answer 1

20% Oxygen

There is a loss of 0.4 grams. # 2.0 -1.6# = 0.4 grams
# 0.4/2.0 xx 100 # = 20%

The oxygen in the copper oxide will be removed when the hydrogen combines with the oxygen to form water (hydrogen oxide).

There were 0.4 grams of oxygen in the compound out of the initial 2.0 grams because the loss of 0.4 grams is the oxygen that was taken out of the Copper Oxide compound.

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Answer 2

The mass of oxygen in copper oxide is the difference between the total mass of copper oxide and the mass of copper obtained. Mass of oxygen in copper oxide = Total mass of copper oxide - Mass of copper obtained Mass of oxygen in copper oxide = 2 grams - 1.6 grams Mass of oxygen in copper oxide = 0.4 grams Percentage of oxygen = (0.4 grams / 2 grams) * 100% Given: Mass of copper obtained = 1.6 grams Total mass of copper oxide = 2 grams

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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