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How would you write the equation for the esterification reaction for acetic acid and ethyl alcohol to form ethyl acetate?

Answer 1

Ruby Allen

#"Acetic acid + ethyl alcohol"rarr"Ethyl acetate + water...."#

or using symbols...

#"H"_3"CC(=O)OH + HOCH"_2"CH"_3 stackrel(Delta, "H"^+)rarr#

#"H"_3"CC(=O)OCH"_2"CH"_3 +"H"_2"O"#

An alternative would be to heat the acid during reflux to produce acid halide.

#"H"_3"CC(=O)OH + SOCl"_2 rarr"H"_3"CC(=O)Cl+HCl(g)"uarr+"SO"_2uarr#

Additionally, one equivalent of a non-nucleophilic base is present when the acid halide is treated with alcohol or amine.

#"R'C(=O)Cl +HOR" stackrel("Et"_3"N")rarr"R'C(=O)OR" "+Et"_3"N"*"HCl"darr#

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Answer 2

Ava Andrews

The equation for the esterification reaction between acetic acid and ethyl alcohol to form ethyl acetate is:

CH3COOH + C2H5OH → CH3COOC2H5 + H2O

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.