How would you write a chemical equation for addition reactions to produce 3-hydroxy-3-methylhexane?
I would use the acid-catalyzed hydration of 3-methylhex-2-ene.
The hydration of an alkene follows the Markovnikov rule: The
Thus, the
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The chemical equation for the addition reaction to produce 3-hydroxy-3-methylhexane can be represented as follows:
[ \text{2-Methylpropene} + \text{Water} \rightarrow \text{3-Hydroxy-3-methylhexane} ]
Alternatively:
[ \text{CH}_3-\text{C}(\text{CH}_3)=\text{CH}_2 + \text{H}_2\text{O} \rightarrow \text{CH}_3-\text{C}(\text{OH})(\text{CH}_3)-\text{CH}_2-\text{CH}_2-\text{CH}_3 ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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