# How would you solve the system of these two linear equations: #2x + 3y = -1# and #x - 2y = 3#? Enter your solution as an ordered pair (x,y).

Given,

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To solve the system of linear equations 2x + 3y = -1 and x - 2y = 3, you can use the method of substitution or elimination. Here, we'll use the method of substitution.

From the second equation x - 2y = 3, we can rearrange it to get x = 3 + 2y.

Now substitute this expression for x into the first equation: 2(3 + 2y) + 3y = -1.

Solve for y: 6 + 4y + 3y = -1 => 7y = -7 => y = -1.

Now that we have the value of y, substitute it back into either equation to find the value of x. Let's use the second equation x - 2y = 3: x - 2(-1) = 3 => x + 2 = 3 => x = 1.

Therefore, the solution to the system of equations is (1, -1).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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