How would you solve #sqrt(x+10)=-3#?

Answer 1

In the set of real numbers the equation #sqrt(10+x)=-3# has no solutions because the left part is always positive or equal to zero for #x=-10# and the right part is always negative.

If you see the graph of both functions #y=sqrt[x+10]# (red line) and #y=-3# (blue line)
it is apparent that no real solutions exist.

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Answer 2

x = -1

Well

#sqrt(x+10) = -3#

Square both sides

#x +10= 9#
#x = -1# So
#sqrt 9 = +-3#
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Answer 3

To solve the equation sqrt(x+10)=-3, we need to isolate the variable x.

First, we square both sides of the equation to eliminate the square root: (sqrt(x+10))^2 = (-3)^2.

This simplifies to x + 10 = 9.

Next, we subtract 10 from both sides of the equation: x = 9 - 10.

Simplifying further, x = -1.

Therefore, the solution to the equation sqrt(x+10)=-3 is x = -1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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