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How would you multiply #(x+8)(x - 8)#?

Answer 1

Isaiah Anthony

#x^2-64# This is a difference of squares where: #(a^2-b^2) = (a+b)(a-b)#

If we let #a=x# and #b=8# #(x^2-8^2) = (x+8)(x-8)#

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Answer 2

Genesis Allen

To multiply (x+8)(x - 8), you can use the distributive property or the FOIL method.

Using the distributive property: (x+8)(x - 8) = x(x) + x(-8) + 8(x) + 8(-8) = x^2 - 8x + 8x - 64 = x^2 - 64

Using the FOIL method: (x+8)(x - 8) = xx + x(-8) + 8x + 8(-8) = x^2 - 8x + 8x - 64 = x^2 - 64

So, (x+8)(x - 8) simplifies to x^2 - 64.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.