How would you draw an alkane that has more than 3 but less than 10 carbon atoms and only primary hydrogens?

Question

Ellie Adams · Accepted Answer

You would have to draw a structure that has only carbon atoms and methyl groups.

A primary hydrogen is a hydrogen on a carbon attached to only ONE other carbon, i.e., a hydrogen atom of a methyl group.

Two alkanes meet the criteria.

One carbon atom + four methyl groups

This gives 2,2-dimethylpropane (five carbon atoms).

Two carbon atoms + six methyl groups

This gives 2,2,3,3-tetramethylbutane (eight carbon atoms).

Zoe Alexander · Answer

undefined Draw a hexane structure with only primary hydrogens on each carbon atom.

Ella Allen · Answer

undefined To draw an alkane with more than 3 but less than 10 carbon atoms and only primary hydrogens, you would follow the rules for alkane structure and hydrogen attachment.

1. Start by drawing a chain of carbon atoms in a straight line. Ensure there are between 4 and 9 carbon atoms in the chain, as specified.
2. Attach hydrogen atoms to each carbon atom in the chain. For primary hydrogens, each carbon atom should have no more than one hydrogen attached, except for the terminal carbon atoms, which will have two hydrogen atoms.
3. Ensure that no carbon atom in the chain has more than three attached hydrogen atoms, as this would violate the condition for primary hydrogens.
4. Do not draw any branches or substituents on the carbon chain, as this would introduce secondary or tertiary hydrogens, which are not allowed in this scenario.

By following these guidelines, you can draw an alkane with the specified criteria: more than 3 but less than 10 carbon atoms and only primary hydrogens. The specific structure will depend on the number of carbon atoms chosen within the given range.