How would you construct a balanced equation for the reaction between X and water to form the hydroxide, XOH, and a gas?

Answer 1

Here's how I would do it.

Since the metal forms the hydroxide #"XOH"#, it must be an alkali metal.
That means the gas it creates is hydrogen, #"H"_2#.

The imbalanced formula is

#"X" color(white)(l)+ "H"_2"O" → "XOH" + "H"_2#
Step 1. Start by putting a #1# in front of the most complicated formula. Let's pick #"H"_2"O"#.
#"X" color(white)(l)+ color(red)(1)"H"_2"O" → "XOH" + "H"_2"O"#.
Step 2. Balance #"O"#.
Put a 1 in front of #"XOH"#.
#"X"color(white)(l) + color(red)(1)"H"_2"O" → color(blue)(1)"XOH" + "H"_2#
Step 3. Balance #"H"#.
There is no way to balance #"H"# without using fractions.
We start over, multiplying all our old coefficients by #2#.
#"X"color(white)(l) + color(red)(2)"H"_2"O" → color(blue)(2)"XOH" + "H"_2#
Now, we have fixed 4 #"H"# atoms on the left and 2 on the right.
We can get 4 #"H"# atoms on the right by putting a 1 in front of #"H"_2#.
#"X"color(white)(l) + color(red)(2)"H"_2"O" → color(blue)(2)"XOH" + color(orange)(1)"H"_2#
Step 4. Finally, balance #"X"#.
Put a #2# in front of #"X"#.
#color(green)(2)"X" + color(red)(2)"H"_2"O" → color(blue)(2)"XOH" + color(orange)(1)"H"_2#

This should bring the equation into balance.

Step 5: Verify the atoms' equilibrium.

#"Atom"color(white)(m)"LHS"color(white)(m)"RHS"# #stackrel(————————)(color(white)(m)"X"color(white)(mmm)2color(white)(mmll)2)# #color(white)(m)"H"color(white)(mmm)4color(white)(mmll)4# #color(white)(m)"O"color(white)(mmm)2color(white)(mmll)2#

Every atom is in balance.

The equation that is balanced is

#2"X" + 2"H"_2"O" → 2"XOH" + "H"_2#
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Answer 2

To construct a balanced equation for the reaction between X and water to form the hydroxide XOH and a gas, we need to determine the chemical formula of X and the gas produced. Once we have the formulas, we can balance the equation by ensuring that the number of atoms of each element is the same on both sides of the equation. Without knowing the specific identity of X and the gas, it is not possible to provide a balanced equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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