How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--> 2 Na2O?

Answer 1

#4Na + O_2 rarr 2Na_2O#.

By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol #Na_2O# should result.

The molecular mass of natrium oxide is #61.98# #g*mol^(-1)#. If #5# #mol# natrium react, then #5/2# #molxx61.98# #g*mol^(-1)# #=# #154.95# #g# natrium oxide should result.

What have I done in this case? Firstly, I had a balanced chemical equation (this is a crucial step; is it balanced?). Secondly, I converted the molar quantity of product to mass using the stoichiometry. If this is not clear, I'm happy to try again.

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Answer 2

Natalie Anton

Calculate the molar mass of Na2O. Then, use the stoichiometric coefficients to find the mole ratio between Na2O and Na. Finally, multiply the moles of Na2O produced by its molar mass to get the grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--&gt; 2 Na2O?

How would you calculate the number of grams of sodium oxide, Na2O, that will be produced when 5.00 moles react with oxygen given the reaction: 4Na + O2--> 2 Na2O?