How would you balance this chemical equation? #As_2O_3 + NaOH -> Na_3AsO + H_2O#?

Answer 1

As₂O₃ + 6NaOH -> 2Na₃AsO₃ + 3H₂O

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Answer 2

#As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O#

It misses the subscript 3 for the Oxygen of the salt in the second member of the equation. In the first member Arsenic has Oxidation number = 3 and it can't change with reacting with NaOH. The correct reaction is the formation of a salt by reaction of NaOH with an acid oxide #As_2O_3 + 6 NaOH = 2 Na_3 AsO_3 + 3 H_2O#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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