How would you balance H2 + O2 = H2O?
2H2 + O2 = 2H2O
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You must first write each component of the original equation separately.
Right side: H = 2 ; O = 1 (number based on the subscripts; no subscript indicates that the element is just 1) Left side: H = 2; O = 2 (number based on the subscripts)
As you can see, the number of O is not balanced yet, even though the number of H is. To correct this, you must multiply the element by 2, and you CANNOT do this by just changing the subscript.
Therefore,
The left side shows H = 2; the right side shows H = 2 x 2 = 4; the right side shows O = 1 x 2 = 2.
Additionally, you multiply H on the left by 2. Therefore,
The left side shows H = 2 x 2 = 4 and the right side shows H = 2 x 2 = 4 and O = 1 x 2 = 2.
Right now, the equation is balanced.
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The balanced equation for the reaction ( \text{H}_2 + \text{O}_2 = \text{H}_2\text{O} ) is:
[ 2\text{H}_2 + \text{O}_2 = 2\text{H}_2\text{O} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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