How would you balance: #C_12H_22O_11 + H_2O -> C_2H_5OH + CO_2#?

Answer 1

#C_12 H_22 O_11 + H_2 O -> 4 C_2 H_5 OH + 4 CO_2#

#C_12 H_22 O_11 + H_2 O -> C_2 H_5 OH + CO_2#
Counting the occurrences of #C#, #H# and #O# on the left hand side we have half as many #C# atoms (#12#) as #H# or #O# (#24#).

Since the right side already has the same numbers for C, H, and O, all we need to do is find the appropriate multiplier for it.

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Answer 2

C12H22O11 + 12 H2O -> 4 C2H5OH + 11 CO2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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