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How would this inequality be graphed #x + 6 > 13#?

Answer 1

Isaiah Anthony

Refer to the explanation.

#x+6>13#

Subtract #6# from both sides.

#x>13-6#

Simplify.

#x>7#

Draw a vertical dashed line at #x=7#. The dashed line means that #x=7# is not part of the graph. Then shade the area to the right of the dashed line to represent #x>7#.

graph{x>7 [-16.02, 16, -8.01, 8.01]}

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Answer 2

Julia Adams

To graph the inequality ( x + 6 > 13 ), first, subtract 6 from both sides to isolate x: ( x > 7 ). Then, draw a number line and mark a solid circle at 7 (since it's greater than, not equal to), and shade to the right of 7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How would this inequality be graphed #x + 6 &gt; 13#?

How would this inequality be graphed #x + 6 > 13#?