How would potassium hydroxide react hydrochloric acid?

Answer 1

This one is easy:

#"Acid + base "rarr" Salt and water"#

And here we got a strong base, potassium hydroxide, and a strong acid, in aqueous solution. Neutralization occurs with the formation of a soluble salt, potassium chloride....and so...we got...

#KOH(aq) +HCl(aq) rarr KCl(aq) +H_2O(l)#
And at the equivalence point, the #pH=7#, i.e. strong acid and strong base gives a NEUTRAL solution.

And such a reaction could be performed quantitatively, i.e. by titrimetry ... provided that we knows volumes, and at least one of the molar concentrations.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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