How would I write an ionic equation to show the formation of ions from sulfur, calcium and arsenic?

Answer 1

Well we would assign oxidation states of...#S(-II), Ca(+II), As(-III)# respectively....

Thus, in a formal sense, we could write.

#S+2e^(-) rarr S^(2-)#
#Ca rarr Ca^(2+) + 2e^(-)#
#As+3e^(-) rarr As^(3-)#

These are individual redox reactions, of course.

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Answer 2

The dissociation of each compound into its constituent ions would be represented to write an ionic equation that would show the formation of ions from sulfur, calcium, and arsenic. Sulfur typically forms the ( \text{S}^{2-} ) ion, while calcium forms the ( \text{Ca}^{2+} ) ion. Arsenic can form several ions, but let's consider ( \text{As}^{3-} ) ion for simplicity. The ionic equation would be: [ \text{S} + \text{Ca} + \text{As} \rightarrow \text{S}^{2-} + \text{Ca}^{2+} + \text{As}^{3-} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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