# How to you find the general solution of #sqrt(x^2-9)y'=5x#?

Then:

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To find the general solution of the differential equation ( \sqrt{x^2 - 9} y' = 5x ), you can follow these steps:

- Separate the variables by bringing ( y' ) to one side and ( x ) to the other side.
- Integrate both sides with respect to ( x ).
- Solve for ( y ) to obtain the general solution.

Following these steps, the general solution can be found as:

[ y = \frac{5}{3} \sqrt{x^2 - 9} + C ]

Where ( C ) is the constant of integration.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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