How to you find the general solution of #(dr)/(ds)=0.05r#?
# r = Ae^(0.05s) #
We have:
Which is a First Order linear separable DE. We can simply separate the variables to get
Then integrating gives:
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To find the general solution of the differential equation (dr)/(ds) = 0.05r, you can separate the variables and integrate both sides. Here's the process:

Separate variables: (dr)/(r) = 0.05ds

Integrate both sides: ∫(1/r) dr = ∫0.05 ds

Solve the integrals: lnr = 0.05s + C

Solve for r: r = Ce^(0.05s)
Where C is the constant of integration. This equation represents the general solution to the given differential equation.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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