How to solve for x?

Question

Using the theorem: if three parallel lines intersect two transversals, then they divide the transversals proportionally

Allison Allen · Accepted Answer

For leftmost transversal: #x~~25.7#
For rightmost transversal: #x=33# The angles represented by 5x and 15 are on the same side of the transversal, so we know that the sum of those two angles will add up to 180 degrees. Consider the following equation: #5x+15=180# #=>5x=165# #=>x=165/5# #x=33# degrees x is equal to 33 degrees. For the leftmost transversal, we will have to set up another equation involving 4x and 3x. Again, they are on the same transversal, so we can set the sum equal to 180 degrees. #4x+3x=180# #=>7x=180# #=>x=180/7# #=>x~~25.7# degrees Plug in the x-values for the corresponding angles, and you should get 4x+3x equaling 180 and 5x+15 also equaling 180 degrees.

Sophia Alfred · Answer

undefined To solve for x, we need to know the specific equation or problem that involves x. Depending on the equation or problem, there are various methods and techniques for solving for x, such as:

1. Algebraic manipulation: Rearrange the equation to isolate x on one side.
2. Factoring: Factor the equation and set each factor equal to zero.
3. Quadratic formula: Use the quadratic formula $x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}$ to solve quadratic equations.
4. Completing the square: Convert the equation into the form $ax^2 + bx + c = 0$ and complete the square to solve.
5. Graphical methods: Graph the equation and find the x-intercepts.
6. Numerical methods: Use numerical techniques like Newton's method or bisection method to approximate the solutions.
7. Trigonometric identities: Use trigonometric identities to solve trigonometric equations.
8. Exponential and logarithmic equations: Use properties of exponents and logarithms to solve equations involving exponential or logarithmic functions.

Without knowing the specific equation or problem involving x, it's not possible to provide a more detailed solution method. If you provide the equation or problem you need help with, I can offer a more tailored explanation on how to solve for x.