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How to find the x and y-intercept given #5y=5x+15#?

Answer 1

The x-intercept is the value of #x# on the x-axis where the line represented by the equation crosses the x-axis. For all points on the x-axis, #y=0# #5y=5x+15# becomes #5(0)=5x+15# on the x-axis. #x=-3# The x-intercept is #(-3)#

Similarly for the y-intercept #5y = 5(0)+15# #y=3# The y-intercept is #3#

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Answer 2

Abigail Allen

To find the x-intercept, set y to 0 and solve for x. To find the y-intercept, set x to 0 and solve for y. For the equation 5y = 5x + 15:

x-intercept: Set y = 0, then solve for x.
5(0) = 5x + 15
0 = 5x + 15
-15 = 5x
x = -3

So, the x-intercept is (-3, 0).

y-intercept: Set x = 0, then solve for y.
5y = 5(0) + 15
5y = 15
y = 3

So, the y-intercept is (0, 3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.