How to find the x and y-intercept given # 2x-y=4#?

Answer 1
The x-intercept is the point #P_1= (2, 0)# and the y-intercept is the point #P_2 = (0, -4)#

Firstly, let's write your function in a standard form :

#2x-y=4 => y=2x-4#
When you seek the x-intercept, there is one information you know : the #y# value of the intercept, its ordinate #= 0#. Thus, you have a point #(x, y) = (x, 0)#.
You can now replace the #y# in your equation with #0# :
#0 = 2x - 4 => 2x = 4 => x = 2#
The x-intercept is the point #P_1 = (2, 0)#.
Same thing for the y-intercept except that the information you know is the #x# value of the intercept, the ordinate, which is #= 0#. Thus, your have a second point #(x, y) = (0, y)#.
Let's replace the #x# in the equation with #0# :
#y = 2*0 - 4 = -4#.
The y-intercept is the point #P_2 = (0, -4)#.

That's it.

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Answer 2

To find the x-intercept, set y = 0 and solve for x. To find the y-intercept, set x = 0 and solve for y.

For the given equation 2x - y = 4:

x-intercept: 2x - 0 = 4 2x = 4 x = 2

y-intercept: 2(0) - y = 4 -y = 4 y = -4

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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