# How to find the density of silver if given the density of gold?

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So gold's density is 19.3 g/#cm^3# and the placement of silver and gold's atoms in the crystallstructure are the same and also both have the atomradius of 144 pm.

What i don't understand is how to calculate the density of silver from all of this. What formula should i use to find this?

Thank you!

So gold's density is 19.3 g/

What i don't understand is how to calculate the density of silver from all of this. What formula should i use to find this?

Thank you!

Here's what I got.

This equation will be your go-to tool in this situation.

Here

The problem now indicates that the radius of the gold and silver atoms in the crystal structure is the same, and their positions are exactly the same.

It is sufficient to understand that those values are the same, even if you are unaware of what they are.

Since both elements' Avogadro's constant is the same, the equation above can be rearranged as

In exchange for gold, you will have

With silver, you'll have

To find, divide these two equations.

This is the same as

According to this equation, the only reason for the difference in density between gold and silver is the different masses of the atoms that comprise each element.

A cursory examination of the periodic table reveals that

Silver will therefore have a density of equal to

Three sig figs are used to round the result.

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Silver and gold have different densities; you cannot determine the density of silver by using the density of gold alone. The densities of each metal are different.

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