# How to differentiate 3/π sinx°?

Let,

So,

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To differentiate ( \frac{3}{\pi} \sin(x) ):

Apply the product rule, where ( u = \frac{3}{\pi} ) and ( v = \sin(x) ).

( \frac{d}{dx}(uv) = u'v + uv' )

( \frac{d}{dx}\left(\frac{3}{\pi} \sin(x)\right) = \frac{d}{dx}\left(\frac{3}{\pi}\right) \sin(x) + \frac{3}{\pi} \frac{d}{dx}(\sin(x)) )

The derivative of ( \frac{3}{\pi} ) with respect to ( x ) is 0 since it's a constant.

The derivative of ( \sin(x) ) with respect to ( x ) is ( \cos(x) ).

Therefore, the derivative of ( \frac{3}{\pi} \sin(x) ) with respect to ( x ) is ( \frac{3}{\pi} \cos(x) ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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