How to construct linear equations Q2b) Q11 and Q13?
I've found the formula for a which is #r=(v+mu)/(m+1)# . But I could construct equation for c without getting a bizarre answer.
For questions 11, I got the equation 10x+5(41-2x)=205 but x=0 in this case.
And lucky last questions 13
I did x=Apollo y=aph and z=ad
Z=x+7200 y=x-4000
So we have x+x+7200-400=303200
And go x=98800, complete different to the answer. Can't someone please correct my mistake? And I will love you forever:)
I've found the formula for a which is
For questions 11, I got the equation 10x+5(41-2x)=205 but x=0 in this case.
And lucky last questions 13
I did x=Apollo y=aph and z=ad
Z=x+7200 y=x-4000
So we have x+x+7200-400=303200
And go x=98800, complete different to the answer. Can't someone please correct my mistake? And I will love you forever:)
2(b)
(11) We have
(13) Mr. Aphrodite earn
2(b)
(13)
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To construct linear equations Q2b), Q11, and Q13, follow these steps:
-
Q2b):
- Identify the slope (m) and y-intercept (b) from the given information or context.
- Write the equation in slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
-
Q11):
- Determine two points that lie on the line.
- Calculate the slope (m) using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points.
- Choose one of the points and use it to solve for the y-intercept (b) using the formula: y = mx + b.
-
Q13):
- If the equation represents a line passing through the origin (0,0), the equation will be in the form y = mx, where m is the slope.
- If the equation represents a line parallel to the y-axis, it will be in the form x = c, where c is a constant.
- If the equation represents a line parallel to the x-axis, it will be in the form y = c, where c is a constant.
Ensure to substitute the appropriate values and constants into the equations to form the desired linear equations for Q2b), Q11, and Q13.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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