How to answer these using geometric progression formula ?
Given the third term and the fourth term for a geometric progression is #75 and 375# respectively. Find the sum of the first seven terms after the third term
Given the third term and the fourth term for a geometric progression is
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To answer questions using the geometric progression formula, follow these steps:

Find the common ratio (r): Divide any term by the preceding term to find the common ratio.

Determine the nth term (Tn): Use the formula Tn = a * r^(n1), where "a" is the first term and "n" is the term number.

Find the sum of the first n terms (Sn): Use the formula Sn = a * (1  r^n) / (1  r), where "a" is the first term and "n" is the number of terms.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
 Find the sum of the first n terms of the series : #1 + 2(1+1/n) + 3(1+1/n)^2 + 4(1+1/n)^3.......#?
 Solving using geometric Series, #sqrt(2)/2, 1/2, 2^(3/2)/8,1/4#?
 Find the nth term An of the geometric sequence described below where r is the common ratio. Kind of confused on what to do?
 How do you find the sum of each arithmetic series #50+44+38+...+8#?
 How do you find the sum of the first 20 terms of the sequence 1, 3, 9,...?
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