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How much work would it take to push a #9 kg # weight up a # 1 m # plane that is at an incline of # pi / 6 #?

Answer 1

Julia Aguilar

#W=44,145J#

#theta=cancel(pi)/6*180/cancel(pi)=30^o# #h=1*sin 30^o=1*0*5=0.5 m# #W=m*g*h=9*9,81*0,5# #W=44,145J#

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Answer 2

Charlotte Aaron

The work done to push a weight up an inclined plane can be calculated using the formula: [ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) ]

Given: Mass of the weight, (m = 9 \text{ kg}), Height of the inclined plane, (h = 1 \text{ m}), Angle of inclination, (\theta = \frac{\pi}{6}).

To find the force required to push the weight up the inclined plane, we use the formula: [ \text{Force} = \text{Weight} \times \sin(\theta) ] where Weight = mass × gravity ((9.8 \text{ m/s}^2)).

Then, substitute the values into the formula for work to calculate the total work done.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.