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How much work would it take to push a # 6 kg # weight up a # 2 m # plane that is at an incline of # pi / 4 #?

Answer 1

#"Work="E_p=82,99 J#


#m:6 kg#
#l=2m#
#alpha=pi/4#

#h=l.sin pi/4=2*sqrt2/2#

#h=sqrt2=1,41 m#

#"Work="E_p=m*g*h#

#"Work="E_p=6*9,81*1,41#

#"Work="E_p=82,99 J#

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Answer 2

The work required to push the 6 kg weight up a 2 m plane at an incline of π/4 radians can be calculated using the formula:

( \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) )

Where:

  • Force = Weight × gravitational acceleration
  • Weight = mass × gravitational acceleration
  • Distance = 2 m (length of the incline)
  • θ (theta) = π/4 radians

Plugging in the values:

  • Weight = 6 kg × 9.8 m/s²
  • Force = Weight × sin(π/4)
  • Work = Force × Distance × cos(π/4)

After calculating the force and plugging it into the work formula, you'll get the work done.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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