How much work would it take to push a # 4 kg # weight up a # 15 m # plane that is at an incline of # pi / 4 #?

Answer 1

#416.203\ J#

Assuming that there is no friction on the plane i.e. there is no loss of energy then the work done, on the weight of #4\ kg# to push up a distance of #15\ m# on the plane inclined at an angle #\theta=\pi/4# , is equal to the change in potential energy to lift weight to a vertical height #15\sin(\pi/4)# given as follows

#Mgh#

#=4\cdot 9.81\cdot 15\sin(\pi/4)#

#=416.203\ J#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Amelia Adams

The work done is ( W = mgh \cos(\theta) ), where ( m = 4 \ \text{kg} ), ( g ) is the acceleration due to gravity, ( h = 15 \ \text{m} ), and ( \theta = \frac{\pi}{4} ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.